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(2x^2)+2=4x
We move all terms to the left:
(2x^2)+2-(4x)=0
a = 2; b = -4; c = +2;
Δ = b2-4ac
Δ = -42-4·2·2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{4}{4}=1$
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